algebraic expressions Model Questions & Answers, Practice Test for ibps clerk prelims 2023

Question :11

Directions :
In each of the following questions two equations are given. You have to solve them and give answer

  1. if x > y
  2. if x < y
  3. if x = y
  4. if x ≥ y
  5. if x ≤ y

I. x = $√256$
II. y = $(– 4)^2$

Answer: (d)

I. x = $√256$ = 16

II. y = ${(– 4)}^2$ = 16

Hence, x = y

Question :12

One-third of Ramani's savings in National Savings Certificate is equal to one-half of his savings in Public Provident Fund. If he has Rs.150000 as total savings, how much he saved in Public Provident Fund?

Answer: (c)

Ratio of Ramani's savings in NSC and PPF = 3 : 2

His savings in PPF = $2/5$ × 150000 = 60000

Question :13

In a two-digit number, the digit at unit place is 1 more than twice of the digit at tens place. If the digit at unit and tens place be interchanged, then the difference between the new number and original number is less than 1 to that of original number. What is the original number?

Answer: (b)

Let the original number be l0 x + y

y = 2x + 1....(i)

and (l0y + x) – (10x + y) = 10x + y – 1

or, 9y – 9x = l0 x + y – 1

or, l9x – 8y = 1 ...(ii)

Putting the value of (i) in equation (ii) we get,

19x – 8 (2x + 1) = 1

or, 19x – 16x – 8 = 1

or, 3x = 9 or, x = 3

So, y = 2 × 3 + 1 = 7

∴ original number = 10 × 3 + 7 = 37

Question :14

Directions :
In each of the following questions two equations are given. You have to solve them and give answer

  1. if x > y
  2. if x < y
  3. if x = y
  4. if x ≥ y
  5. if x ≤ y

I. $y^2$ – 6y + 9 = 0
II. $x^2$ + 2x – 3 = 0

Answer: (e)

I. $y^2$ – 6y + 9 = 0

or,${(y – 3)}^2$ = 0 or, y = 3

II. $x^2$ + 2x – 3 = 0 or, x = 1, – 3

Hence, y > x

Question :15

A two-digit number is seven times the sum of its digits. If each digit is increased by 2, the number thus obtained is 4 more than six times the sum of its digits. Find the number.

Answer: (c)

Let the two-digit number be 10 x + y

10 x + y = 7(x + y)⇒x = 2y...(i)

10 (x + 2) + y + 2 = 6 (x + y + 4) + 4

or 10x + y + 22 = 6x + 6y + 28⇒4x – 5y = 6 ... (ii)

Solving equations (i) and (ii), we get x = 4 and y = 2

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